X- ray diffraction (XRD) is a technique used to analyze te e crystal structure of materials. It provides data that can be use t calculate interplanar spacings, which ire distrances between atomic planes in a crystal. Understanding how to interpret XRD data is essential for material specialization and analysis.

Understanding X- ray Diffraction Data

XRD data is typically presented as a diffraction Pattern, showing peaks at specific angles. These peaks correspond to to thee diffraction of X- rays by the crystal planes. The position of each peak is related te te interplanar spacing thripg Bragg 's Law.

Kalkulating Interplanar Spacings

Bragg 's Law is the fundamentaltal equation used to calculate interplanar spatings. It i s expressed as:

(zob. pkt 2.1.1.1 niniejszego załącznika)

Kiedy:

  • (1); (1); (1); (1); (1); (1); (1); (1); (1); (2); (1); (2); (2); (2); (2); (2); (2); (2); (2); (2); (2); (3); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4) (4); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4); (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4) (4
  • Xi1; Xi1; FLT: 0 Xi3; Xi1; Xi1; FLT: 1 Xi3; Xi3; is the flonegth of the X- ray
  • (zob. pkt 2.2.1.1.1 niniejszego załącznika)
  • (zob. pkt 2.1.1.1 niniejszego załącznika)

Rearranging thee equation to o solve for d gives:

(2 sin θ) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1) (1 (1) (1) (1) (1 (1) (1 (1 (3) (1) (1 (1) (1 (1) (1) (1) (1 (1) (1 (1) (1) (3) (1 (3) (3) (3) (1) (3) (1 (1 (1) (1) (1) (1) (1 (1) (1) (1) (1) (1) (1) (

Appliing the Calculation

Te determinate thee interplanar spacing, measure thee diffraction angle (2θ) frem thee Pattern. Divide this angle by 2 t find θ. Usie the known florength of thee X- ray source, typically 1.54 Å for Cu Kα radiation. Plug these values into the formula ta calculate d.

For example, if a peak appears at 2θ = 30 °, then θ = 15 °. Using λ = 1,54 Å:

(2 sin 15 °)