Step- by- step Guidete tu Calculating Shear en Bending Stresses Kształty
This guides provides a clear process for calculating shear and d bending stresses in shafts. understanding these stresses is essential for designing safe and d efficient mechanical contexents.
Understanding Shear and d Bending Stresses
Shear stres events when forces are applied parallel to te cross- section of a shaft, causing layers to slide paste each texr. Bending stress result from moments that cause the shaft to bend, creating tension one one side and compression thee tehr.
Calculating Shear Stres
Te shear stress ((tau)) at a point in a shaft is calculated using thee formula:
(tau = frac {V times Q} {I times t})
Kiedy:
- Xi1; Xi1; FLT: 0 Xi3; Xi3; V Xi1; Xi1; FLT: 1 Xi3; Xi3; = shear force at te te section
- Xi1; Xi1; FLT: 0 Xi3; Xi3; Q Xi1; Xi1; FLT: 1 Xi3; Xi3; = first momento of area about the neutral axi
- Xi1; Xi1; FLT: 0 Xi3; Xi3; I Xi1; Xi1; FLT: 1 Xi3; Xi3; = second momento of area of the shaft
- Xi1; Xi1; FLT: 0 Xi3; Xi3; t Xi1; Xi1; FLT: 1 Xi3; Xi3; = xixness at the point of interest
Calculating Bending Stress
Bending stress ((sigma)) is determinaed using the flexure formula:
(sigma = frac {M times y} {I})
Kiedy:
- = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
- (zob. pkt 2.1.1.1 niniejszego załącznika)
- Xi1; Xi1; FLT: 0 Xi3; Xi3; I Xi1; Xi1; FLT: 1 Xi3; Xi3; = second momento of area
Badanie Calculation
Poproś o dodatkowe doświadczenia a shear force of 10,000 N and a bending momento of 500 Nm. The shaft 's second momento of area (I) is 8.33 × 10 giganty1; giganty1; FLT: 0 giganty3; Giganty3; -6 giganty1; GHT: 1 giganty3; GHT: 1 gigantyna; m gestione 1; GHT: 2 gigantyna 3; GHT: 3 gigantyna 3; GHF: 3. The distance from the neutral axitos the outer fiber (y) is 0.05 m.
Spres Shear:
(tau = frac {V times Q} {I times t})
Załóżmy, że uniform distribution, thee shear stres is approxiately:
(tau approx frac {10,000 times 0.0001} {8.33 times 10 ^ {-6}}) = 120 Pa Xi1; Xi1; FLT: 1 Xi3; Xi3;
Bending stress:
(sigma = frac {M times y} {I})
Kalkulating:
(sigma = frac {500 times 0,05} {8.33 times 10 ^ {-6}}) = 300,000 Pa = 1; Xen1; FLT: 1 Xen3; Xen3; Xen3;