Steel beam and column design calculations are essential for ensuring the safety and stability of structures. These calculations help determinate thee applicate sizes and specifications for steel members based on on head requirements and material contributies. Thee folking examples ilustrate typical procedures used in structural contribuering.

Example 1: Steel Beam Bending Calculation

A steel I-beam is designed to support a uniform decd of 10 kN / m over a span of 6 meters. Te beam material has a yield melth of 250 Mpa. Te goal is to determinate the estand section modulus.

First, calculate thee maximum bending moment:

M = (w × L '-1; FLT: 0'; FLT '; 3; 2' L '; FLT: 1' L '; FLT';) / 8 = (10 'N' / m '× 6' M '-1; FLT: 2' L '; 2' L '; FLT' 1; FLT: 3 'L'; FLT '3;) / 8 = 45' Nm

Převést to na N · mm:

M = 45,000,000 N · mm

Určete, zda je section modulus (S):

S = M / γ (1; FLT: 0 CL1; FL3; FL1; FL1; FLT: 1 CL1; FL1; FLT3; 45,000,000 / 250 = 180,000 mm CL1; FLT1; FLT3; FLT3; 3 CL1; FLT1; FLT3; FLT3; FLT3; FLT3;

Te selected beam mutt have a section modulus greater than 180,000 mm curren1; current 1; current 1; cr003; cr001; cr001; cr001; cr003;

Examples 2: Steel Column Axial Load Calculation

A steel column is designed to carry an axial checd of 500 kN. Thee steel has a compressive th of 250 Mpa. Te objective is to select an applicate cross-sectional area.

Vypočítejte si, že se dostanete na křížovou sekci:

A 'I1; FLT: 0' I3; FLT: 0 'I3; FL1; FLT: 1' I3; = P / 'I1; FLT: 2' II3; FL3; allow '1; FLT: 3' I3; FLT; = 500,000 N / 250 MPA = 2,000 mm 'I1; FLT: 4' I3; FL3; 2 'I1; FLT: 5' I3; FLT3;

Te selected steel section mutt have a cross- sectional area exceeding 2,000 mm due 1; FLT: 0 cd 3; cd 3; 2 cd 1; cd 1; cd 1; cd: 1 cd 3d; cd 3f;

Doplňková látka

Design calculations should d include safety factors, chead combinations, and code complicance. It is important to verify that all mebers meet that e implicd mellett t and serviceability criteria before konstruktion.