Capacitive and piezoeletric sensors are widely used in various industries for mejuring fyzical quantities such as pressure, akceleration, and displacement. Understanding their principles helps in selectin thee applicate sensor for specific applications and in performing exaccerate calculations related to their operation.

Principy pro senzor Capacitive

Capacitive sensors operate based on changes in capacitance caused by variations in te distance or dielectric accesties between een two dictive plates. Won a fyzical quantity causes these plates to move or alter thee dielectric material, thecaditance changes accordingly.

Te capacitance (C) is calculated using thea formula:

CLAS1; CLAS1; CLAS3; CLAS3; CLAS3; CLAS3M; epsilon; A / d CLAS1; CLAS1; CLAS1; CLAS3; CLAS3c; CLAS3CCAS3CRAS3CRAS3CRAS3CRAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLAS3CLASPERASPERASPERASPERASPERASPERASPERASPERASPERASPERASPERASPERASPERASPERASPERASSIMATRASSIMATIRESSIMATRASSIMATRASSIMATIRESSIONS;

kde se nachází; epsilon; is te permittivity of te dielectric material, A is te area of te plates, and d is t e distance between them.

Principy pro piezoeletrické senzory

Piezoeletric sensors generate an electric charge when subjected to mechanical stress. This applity is due to te crystal structure of piezoelectric materials, which produces a voltage proportional to te applied force or pressure.

Te contraship between the applied force (F) and the generate voltage (V) can be expressed as:

CLAS1; CLAS1; CLAS3; CLAS3; V = d * F CLAS1; CLAS1; CLAS1; CLAS3; CLAS3;

Výběrové zkoušky

Example 1: Capacitive Sensor

A capacitive sensor has an area of 10 cm thes1; FLT: 0 thes3; FL3; 2 thes1; FL1; FLT: 1 hassur; gr3; gr3;, a dielectric permittivity of 8.85 x 10 action 1; FLT: 2 hadn-3s; -12 had1; FLT: 3 had3; gr3; F / m, and the distance been plates changes from 1 mm to 0.9 mm. Calculate te change in capacitance.

Inicial capacitance:

C CLAS1; CLAS1; CLAS1; CLAS3; CLAS3; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS3; CLAS3; CLAS3; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS3; CLAS3; CLAS3; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS3; * 0, 0001 / CLAS3; C3F

Final capacitance:

C CLAS1; CLAS1; CLAS1; CLAS3; CLAS3; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS3; CLAS3; CLAS3; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS3; CLAS3; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS3; * 0.0001 / 0.0009 = 9.83 x CLAS1; CLAS1; CLAS1; CLAS3; CRAS3; CF

Change in capacitance: 9.83 x 10 CLAS1; CLAS1; FLT: 0 CLAS3; CLAS3; -12 CLAS1; CLAS1; CLAS1; CLAS3; - 8.85 x 1CLAS1; CLAS1; CLAS3; CLAS1; CLAS1; CLAS1; CLAS1; CLAS1; CLAS3; -1CLAS3; CLAS3; CLAS3; CLAS3; CLAS3; CATS3; CRAS3FRAS3FF;

Example 2: Piezoeletric Sensor

A piezoeletric sensor produces a voltage of 5 V when a force of 10 N is applied. Find thee voltage generate when thee force increares to 15 N, assuming linear behavior.

Using thee contenship V = d * F, and assuming d leabs constant:

V CLAS1; CLAS1; CLAS3; CLAS3; 1 CLAS1; CLAS1; CLAS3; CLAS3; CLAS3; = d * 10 N = 5 V

d = 5 V / 10 N = 0, 5 V / N

Fór 15 N:

V CLAS1; CLAS1; CLAS3; CLAS3; 2 CLAS1; CLAS1; CLAS3; CLAS3; CLAS3; = 0, 5 V / N * 15 N = 7, 5 V