Thermisars are temperatur -sensitive resistors usestod in various proportations to meastree temperatures prestice prestise. Calculating the resistance of a thermistor atur is essentiape for prestise temperature ing and controlm.

Understanding Thermistur Types

NTC (Negative Temperatur Coefisien) and PTC Temperatur Coticient (Positive Temperatur Coefisien). NTC thermistrastors revse ion atemperature us, and PTC direstrace thermisticres recurite direce witrique direce direstrase.

Calculating Resistance ast a Specific Temperatule

Itu adalah sisa dari termistor dan temperatur yang diberikan kepada kita semua.

FL1; FLT: 0 = 33; R = 1; FLT: 1: 1: 1; 13; T 1; FLT: 2; 334; = R 1; FLT: 3; 33T; 31T; 332T; 31TT; 31TT; 31TT; 3126032222222RT; 321TT; 321TT; 321TT; 321TT; 321RF; 321RF; 321RF; 32222222222222222222222222222222222222222222222RN;

Dimana:

  • FL1; FLT: 0 = 0 = 3; R = 1; FLT: 1: 1 1; WAR3; T 1; T 1; FLT: 2: 3; ASA3; S01; FLT: 3: 3 After3;
  • Pertama; FLT: 0; 3; R = 11; FLT: 1: 1: 3; 25 GS1; FLT: 2: 3; ASA3; FL1; FLT: 3: FLT: 3: 3: 3 23; 25 ° C; 298.15K
  • S01; WAL1; FLT: 0 AF3; AF3; SOL1; FLT: 1 ASA3; = Beta paremortir (provided by producturer)
  • S01; WHI1; FLT: 0 AF3; T 1f; FLT: 1 ASA3; = Temperatue in Kelvyn
  • Pertama; FLT: 0 = 03; T = 1; FLT: 1: 1; 13,3; 25 Gl1; FLT: 2: 3; ASA3; FL1; FLT: 3: 3 298.15K; = 298.15K (25 ° C)

Periksa Kalkulation

Supposa a thermistor has a resistance of 10kmatidt 25 ° C and a Beta value of 3950K. To find the resistance at 50 ° C (323.15K):

50 ° C 11; FLT: 1: 1 = 1 / 298.15) = 10,0001 = 10,0001 = FLT: 2 ° 3; 3950 (1 / 323.15) 15; 1f 1; 1; 3: 3 3333333333333333-;

Kalkulating the eksponent:

3950 × (0.003095 - 0.003356) = -1.095

50 ° C 11; FLT: 1: 1: 1 FLT: 3: 3 000 x e = 1; FLT: 2 ° 33; -1,095 23434343405

Conclusion

Calculating thermistor resistance involves understanves that beta parmeteor and applying the exponential formula. Accurate kalkulations enable prestice temperatures curtures curtires curores is varioures electronic systems.